Georgian tennis player Oksana Kalashnikova claimed her fourth Women's Tennis Association (WTA) doubles win on Sunday as she triumphed in the final of the Hungarian Ladies Open in Budapest.
Kalashnikova paired with Taiwan’s former World No. 1 Su-Wei Hsieh in the doubles category of the WTA competition that ran from February 19-26. The pair was seeded fourth for the Budapest competition.
After winning three playoff rounds from February 22-24, the pair reached Sunday’s final to face Kazakhstan’s Galina Voskoboeva and Australia’s Arina Rodionova.
Great job girls! 1st title for @SuweiHsieh since 2014 @rolandgarros@WTA@OksKalashnikova#Budapest#hunopenpic.twitter.com/2GXBDAIha5
— HUNgarianTENNIS (@HUNgarianTENNIS) February 26, 2017
The match on the Kormoczy Court was won by the Georgian-Taiwanese pair in three sets 6-3, 4-6, 10-4.
Kalashnikova gained 280 WTA ranking points with the win and is now placed as World No. 44 in WTA doubles ranking.
Kalashnikova and Hsieh won the final in three sets. Photo: Hungarian Ladies Open.
Played on hard surface, the Hungarian Ladies Open was held for the first time since its reinstatement as a WTA competition earlier this year.
The singles category of the tournament was won by local favourite Timea Babos who defeated Czech Republic’s Lucie Safarova 6:7, 6:4, 6:3.